To classify two-dimensional figures, focusing on trapezoids, and to draw trapezoids based on given attributes.
Solving word problems involving area in square inches, square feet, etc. Eureka Math Grade 5 Module 4 Lesson 16 Homework Answers Problem 1: Find the area of the rectangles A rectangle with a length of 34three-fourths ft and a width of 23two-thirds Solution: To find the area, multiply length Answer: 12one-half square foot. Part (b): A rectangle with a length of 45four-fifths yd and a width of 34three-fourths Solution: Answer: 35three-fifths square yard. Problem 2: Tiling a Rectangle Problem: Mrs. Midas has a rectangle that is 35three-fifths meter long and 23two-thirds meter wide. She tiles it with smaller tiles that are 13one-third 15one-fifth Solution: First, find the total area of the rectangle: square meters. Next, find the area of one tile: square meters. Finally, divide the total area by the tile area: Answer: She needs 6 tiles. Problem 3: Word Problem (Fabric) Problem: A fabric store has a remnant that is 58five-eighths yard long and 23two-thirds yard wide. What is the area of the remnant? Solution: Multiply length Answer: 5125 over 12 end-fraction square yard. Problem 4: Word Problem (Garden) Problem: A garden is 34three-fourths mile long and 14one-fourth mile wide. What is the area of the garden? Solution: Multiply length Answer: 3163 over 16 end-fraction square mile. Step-by-Step Explanations for Success Eureka Math Lesson 16 Homework 5.4 Answer Key
4/5 × 3/4 = (4×3)/(5×4) = 12/20 = 3/5. Part (b): A rectangle with a length of
Disclaimer: This answer key is intended to assist students with their understanding of the Eureka Math homework assignments. The specific figures in the homework might vary slightly in different editions of the curriculum. She tiles it with smaller tiles that are