σ=PA=80×103 N400×10-6 m2=200×106 Pa=200 MPasigma equals the fraction with numerator cap P and denominator cap A end-fraction equals the fraction with numerator 80 cross 10 cubed N and denominator 400 cross 10 to the negative 6 power m squared end-fraction equals 200 cross 10 to the sixth power Pa equals 200 MPa
Resuelve los problemas propuestos de para ganar agilidad.
Δ=𝜕U𝜕P=∫0π/2M(θ)EI(𝜕M(θ)𝜕P)dscap delta equals the fraction with numerator partial cap U and denominator partial cap P end-fraction equals integral from 0 to pi / 2 of the fraction with numerator cap M open paren theta close paren and denominator cap E cap I end-fraction open paren the fraction with numerator partial cap M open paren theta close paren and denominator partial cap P end-fraction close paren d s Donde el diferencial de arco es . Calculamos la derivada parcial: